-->
ROUTING



N1 = 50 (6 bit) N5 = 2 (2 bit)
N2 = 40 (6 bit) N6 = 2 (2 bit)
N3 = 60 (6 bit) N7 = 2 (2 bit)
N4 = 70 (7 bit)
Alokasi IP = 124.128.0.0/16


Jawaban :

Subnet Mask = 255.255.255.192


Alokasi IP
N1 = 124.128.0.1 - 124.128.0.126
N2 = 124.128.0.129 - 124.128.0.254
N3 = 124.128.1.1 - 124.128.1.126
N4 = 124.128.1.129 - 124.128.1.254
N5 = 124.128.2.1 - 124.128.2.126
N6 = 124.128.2.129 - 124.128.2.254
N7 = 124.128.3.1 - 124.128.3.126


R1
e0 124.128.2.1
e1 124.128.2.129

R2
e0 124.128.2.130
e1 124.128.3.1

R3
e0 124.128.2.2
e1 124.128.0.1
e2 124.128.0.129

R4
e0 124.128.3.2
e1 124.128.1.1
e2 124.128.1.129


Tabel Routing
R1
Destination Network
Gateway
Interface
124.128.2.0 /25
Direct
e0
124.128.2.128 /25
Direct
e1
124.128.0.0 /25
124.128.2.2
e2(R­3­­­­­)
124.128.0.128 /25
124.128.2.2
e2(R­3­­­­­)
124.128.3.0 /25
124.128.2.130
e0(R2)
124.128.1.0 /25
124.128.2.130
e0(R2)
124.128.1.128 /25
124.128.2.130
e0(R2)

R2
Destination Network
Gateway
Interface
124.128.2.128 /25
Direct
e1(R1)
124.128.3.0 /25
Direct
e0(R4)
124.128.1.0 /25
124.128.3.2
e0(R4)
124.128.1.128 /25
124.128.3.2
e0(R4)
124.128.2.0 /25
124.128.2.129
e1(R1)
124.128.0.0 /25
124.128.2.129
e1(R1)
124.128.0.128 /25
124.128.2.129
e1(R1)

R3
Destination Network
Gateway
Interface
124.128.2.0 /25
Direct
e0
124.128.0.0 /25
Direct
e1
124.128.0.128 /25
Direct
e2
124.128.2.128 /25
124.128.2.1
e0(R1)
124.128.3.0 /25
124.128.2.1
e0(R1)
124.128.1.0 /25
124.128.2.1
e0(R1)
124.128.1.128 /25
124.128.2.1
e0(R1)

R4
Destination Network
Gateway
Interface
124.128.3.0 /25
Direct
e0
124.128.1.0 /25
Direct
e1
124.128.1.128 /25
Direct
e2
124.128.2.128 /25
124.128.3.1
e0(R2)
124.128.2.0 /25
124.128.3.1
e0(R2)
124.128.0.0 /25
124.128.3.1
e0(R2)
124.128.0.128 /25
124.128.3.1
e0(R2)



Implementasi Dalam Paket Tracer

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